Question

Question 2

Answer 1

Probably I'm wrong..
During that impact...
Change of momentum:
m(1.00x10^2) + M(0) = (m+M)v
=> v = 100m / (m+M)
Change in energy:
(1/2)m(1.00x10^2)^2 x (1-99%) = (1/2)(m+M)v^2
100m = (m+M) [100m / (m+M)]^2
100 (m+M) = 10000m
100M = 9900m
m/M = 1/99 ?!

Answer 2

probably this part is wrong
-----------------------------------------
(1/2)m(1.00x10^2)^2 x (1-99%) = (1/2)(m+M)v^2
100m = (m+M) [100m / (m+M)]^2
100 (m+M) = 10000m
100M = 9900m
m/M = 1/99
------------------------------------------
(1/2)m(1.00x10^2)^2 x (99%) = (1/2)(M)v^2

Answer 3

better try finding the final velocity of bullet.

Answer 4

Wait... Is energy lost from the bullet transferred the block?

Answer 5

yep!!