x^3+y^3=6xy (4/3, 8/3) find slope
Take the derivative, That makes find the slope very simple
Are you asked to find the slope at that point? BTW, do you know how to take a derivative or a polynomial?
I don't really understand derivatives. That's where the problem starts
The slope at that point
I'll take the derivative for you, could you double check your equation?
x^3+y^3=6xy
alright, the derivative is (x^2-2y)/(2x-y^2), now just plug in the point you have and that will give you the slope of the lline at that point.
I'm getting the slope to be 4/5
How do you get to the derivative though?
What math class/ level are you in?
You just do implicit differentiation. This is because y is part of the equation and it can't be isolated.
high school calculus
Have you done derivatives, or implicit differentiation?
working n implicit
Do you know how to start? Take the derivative dy/dx(x^3+y^3)=d/dx(6xy)
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