Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

CAN SOMEONE PLZ HELP?!!

OpenStudy (anonymous):

OpenStudy (anonymous):

Looks like a binomial situation. Are you familiar with the binomial formula?

OpenStudy (anonymous):

Not A clue.

OpenStudy (anonymous):

That's ok, this can be done without it because the numbers are small enough to not get too cumbersome. First identify your probabilites of success and failure. prob' of success = p=0.3 (has under influence) prob' of failure = q=0.7 (has not under influence) The sample size, n=3.

OpenStudy (anonymous):

The first question is asking for at least one not under influence. You can think of that as the complement of the probability that all three have. i.e. P(at least one didn't) = 1-P(all three did). Does that make sense?

OpenStudy (anonymous):

sorta. I'm just confused on what #'s to use

OpenStudy (anonymous):

If you do it the way I suggested, it's pretty quick. There's a long way to do it that gets the same answer, but who wants to do something the long way? The probability that they all have = 0.3 × 0.3 × 0.3 (multiplication rule for an AND situation).

OpenStudy (anonymous):

So if that's the P(all have), then P(at least one hasn't) is that number subtracted from 1.

OpenStudy (anonymous):

Just for general interest, the long way looks like this: (0.7 × 0.3 × 0.3) × 3 + (0.7 × 0.7 × 0.3) × 3 + (0.7 × 0.7 × 0.7) × 1 [I know, who would want to do it that way?]

OpenStudy (anonymous):

so i do 1-0.027?

OpenStudy (anonymous):

Yep.

OpenStudy (anonymous):

so the answer a) is 0.973?

OpenStudy (anonymous):

(Here's a good overview of basic probability rules http://stattrek.com/probability/probability-rules.aspx?Tutorial=Stat I recommend looking at other pages on that site as well)

OpenStudy (anonymous):

Yes, that would answer question (a). :-)

OpenStudy (anonymous):

[Though, it says to round to four decimal places, so you might want to express it as "0.9730"]

OpenStudy (anonymous):

ok so part b?

OpenStudy (anonymous):

Same kind of reasoning, but you're going to take the complement of P(all have not) = 1-P(at least one has).

OpenStudy (anonymous):

So what is the probability that all three have not operated under the influence of sugar? [While you figure that out, I'm going to go put more sugar in my coffee...]

OpenStudy (anonymous):

lol ok

OpenStudy (anonymous):

is it 0.7?

OpenStudy (anonymous):

0.7 is the probability that one at random has not, but you want to find the probability that three have not.

OpenStudy (anonymous):

well then idk.

OpenStudy (anonymous):

you got this or no?

OpenStudy (anonymous):

Let's talk more about the multiplication rule...

OpenStudy (anonymous):

If you want the probability that all three have not operated under the influence, then that's like . .. let's say the three people are A, B, and C . . . for A to not have, that's a 0.7 prob' for A AND B to not have, that's 0.7×0.7 . . . See where I'm going with this?

OpenStudy (anonymous):

So, once you find the probability that all three have not, then the probability that at least one has = 1 minus that.

OpenStudy (anonymous):

oh ok so i do 0.7 x 0.7 x 0.7 & that =0.343.

OpenStudy (anonymous):

Right . . .

OpenStudy (anonymous):

then 1-0.343=0.657

OpenStudy (anonymous):

so 0.657 is the answer?

OpenStudy (anonymous):

That should be it. You should think through it logically and ask if it makes sense (the last step of any problem solving is the 'reality check.')

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!