Literal Equation problem?
Be patient, I am writing it.
In order to solve the literal equation: \[A = s^{2}\] for s, what should you do to the equation?
\[\forall A\epsilon [0,\infty)\] (For all A be belongs between 0 and infinity [a positive number]) take the square root of both sides.
Square root? Is that s? omg.
\[\sqrt{s^2}=(s^2)^{\frac{1}{2}}=s\] \[\sqrt{s^2}=s=\sqrt{A}\]
I dont know. Look, the problem is that I know that this problem is like algebra, but I am in like math 3 (or pre-algebra) and I do not know all these check mark characters and stuff. I know PEMDAS negative signs exponents, fractions, but thats it. Sorry.
The square root is something you should've learned before pre-algebra. 2*2 = 4 (-2)*(-2) = 4 the square root of 4 = 2, and square root of 4 = -2 Also written like this. \[\sqrt{4}=\pm 2\] In your situation, \[s^2=s*s\] If you take the square root of s^2, you will get s.
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