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one last question integral 0 to infinity dx/sqrt[x]
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\[\int\limits_{0}^{\infty} \frac{ dx }{ \sqrt{x} }\]
= INT x^(-0.5) = x^(0.5) / 0.5 = 2 x^(0.5)
u use the \[\frac{ x^(n+1) }{ n+1 } \] right?
yes - thats what i did you can also write it as 2 sqrt x
then take the limits of 0 to infinity right?
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between the limits 0 and infinity its value is infinity - 0 = infinity
which is diverges right?
yep
kk :3. thank u. gosh i hate when those problems r that simple yet i made it complicated :S
lol - keep practicing
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im hanging in that cal II class. got to get my gpa up back to .3 or 1.3 points
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