Question

Find dy/dx by implicit differentiation
ysin(x^2)=xsin(y^2)

I got:
(dy/dx) sin(x^2) + (y) cos(x^2) (2x) = sin(y^2) + x cos(y^2) (2y) (dy/dx)


(dy/dx) sin(x^2) - 2xy cos(y^2) (dy/dx) = sin(y^2) - 2xy cos(x^2)

(dy/dx) ( sin(x^2) - 2xy cos(y^2) ) = sin(y^2) - 2xy cos(x^2)

(dy/dx) = [ sin(y^2) - 2xy cos(x^2) ] / [ sin(x^2) - 2xy cos(y^2) ]

can someone verify my answer?

Answer 1

(dy/dx) sin(x^2) + (y) cos(x^2) (2x) = sin(y^2) + x cos(y^2) (2y) (dy/dx) is correct

Answer 2

That wasn't my answer ^ lol?

Answer 3

yes. you did it correct.

Answer 4

yes it is ok till end .