Mathematics
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OpenStudy (anonymous):
The zeros for (squareroot of x-1) +
(squareroot of x + 4) -5 is (are)?
Written better below
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OpenStudy (anonymous):
The zeros for \[\sqrt{x-1}+\sqrt{x+4} -5\] is (are)?
jhonyy9 (jhonyy9):
your opinion ?
OpenStudy (anonymous):
(a) x = 5
(b) x = 10; 17
(c) x = 1
(d) x = 4
jhonyy9 (jhonyy9):
ok but how you will get these roots of this function so yes this after you make it equale with zero ?
jhonyy9 (jhonyy9):
came on i wann to help you
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jhonyy9 (jhonyy9):
how do you think what we need to doing in the first step ?
OpenStudy (anonymous):
im not sure
jhonyy9 (jhonyy9):
hope so much that you have learned in your schoole ,or not ?
OpenStudy (anonymous):
i want to square everything but i feel like thats wrong
OpenStudy (anonymous):
can you please walk me through it
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jhonyy9 (jhonyy9):
yes this will be the first step because you know it right that when there is squareroot in afunction first we need to elimine it by squaring it
jhonyy9 (jhonyy9):
so there is sqrt(x-1) +sqrt(x+4) -5 =0
OpenStudy (anonymous):
ok
jhonyy9 (jhonyy9):
sorry my internet conection is wrong
jhonyy9 (jhonyy9):
so in the first step add to both sides 5
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jhonyy9 (jhonyy9):
so what will get
jhonyy9 (jhonyy9):
sqrt(x-1) +sqrt(x+4) =5
OpenStudy (anonymous):
yeah
jhonyy9 (jhonyy9):
now you need to square both sides ,ok ?
OpenStudy (anonymous):
i got that far and it was x-1+x+4=25
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jhonyy9 (jhonyy9):
no you need to square both sides like
a=b
so but in this your case a =((sqrt(x-1) +sqrt(x+4))
ok ?
OpenStudy (anonymous):
ok
jhonyy9 (jhonyy9):
so than you need to us formula (a+b)^2 = ?
hope that you know it
jhonyy9 (jhonyy9):
???
OpenStudy (anonymous):
\[(\sqrt{x-1}+\sqrt{x+4})^{2}=25\]
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OpenStudy (anonymous):
IS that right?
jhonyy9 (jhonyy9):
yes continue it
jhonyy9 (jhonyy9):
do you know formula ?
OpenStudy (anonymous):
no sadly
jhonyy9 (jhonyy9):
so (a+b)^2 =a^2 +2ab +b^2
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jhonyy9 (jhonyy9):
a=sqrt(x-1)
b=sqrt(x+4)
OpenStudy (anonymous):
ok so its \[x ^{2}+3x-4\]
OpenStudy (anonymous):
=25
jhonyy9 (jhonyy9):
so i dont know it just if you write it here all calcules
jhonyy9 (jhonyy9):
sqrt(x-1) +sqrt(x+4)=5
(x-1) +2sqrt((x-1)(x+4)) +(x+4)=25
2sqrt((x-1)(x+4))=25-(x-1)-(x+4)
2sqrt((x-1)(x+4))=25-x+1-x-4
2sqrt((x-1)(x+4))=22-2x
2sqrt((x-1)(x+4))=2(11-x)
sqrt((x-1)(x+4))=11-x
(x-1)(x+4)=121-22x +x^2
x^2 +3x -4=x^2 -22x +121
25x =125
x=5
ok ?
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OpenStudy (anonymous):
ok thank you
jhonyy9 (jhonyy9):
check it please step by step for you can understanding all right
jhonyy9 (jhonyy9):
was my pleasure
good luck
bye
OpenStudy (anonymous):
\[\sqrt{x-1}+\sqrt{x+4}=5\]
OpenStudy (anonymous):
\[(x-1)+2(\sqrt{(x-1)(x+4)}+(x+4)=25\]
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jhonyy9 (jhonyy9):
yes but next the 2 without paranthese
ok ?
OpenStudy (anonymous):
ok