how can I solve for x in terms of other variables? Example included:
p-6/7x=2q
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OpenStudy (anonymous):
so to solve this, I want to get rid of any fractions, because fractions are evil. so i would multiply both sides by 7x. Next i would want to get x on its own. so i would divide both sides by (2 x 7 x q)
OpenStudy (anonymous):
I don't quite understand
OpenStudy (anonymous):
okay multiply both sides of your equation by 7x and type what you get
OpenStudy (anonymous):
oh I made a typo... the fraction in the equation is -6/7
OpenStudy (anonymous):
Would that mean I also multiply by -7, right?
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OpenStudy (anonymous):
\[\frac{-6}{7x} = 2q\] ?
OpenStudy (anonymous):
is that the equation
OpenStudy (anonymous):
no, the equation is p-6/7x=2q
OpenStudy (anonymous):
\[\frac{p-6}{7x} = 2q\] ?
OpenStudy (anonymous):
\[p - \frac{6}{7x} = 2q\] ?
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OpenStudy (anonymous):
use brackets in your equation
OpenStudy (anonymous):
\[p-\frac{ -6 }{ 7x }=2q\]
OpenStudy (anonymous):
so that last one with brackets would be p -(6/7x) = 2q
OpenStudy (anonymous):
p minus minus 6, or p minus 6?
OpenStudy (anonymous):
first one?
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OpenStudy (anonymous):
yeah p- negative six over seven and the x is in the middle of the equation next to the line between the 6 and 7
OpenStudy (anonymous):
cool awesome
OpenStudy (anonymous):
okay so - - 6 = + 6 right?
OpenStudy (anonymous):
opps....forget the p minues negative six its just p minus 6
OpenStudy (anonymous):
so....p minues negative 6 over 7x equals 2q
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OpenStudy (anonymous):
right okay so firstly you want to minus both sides by p. type what you get
OpenStudy (anonymous):
i would get -6/7x=2q-p
OpenStudy (anonymous):
yeah you would, now multiply both sides by 7x, write the right hand side as 7x(2q-p)
OpenStudy (anonymous):
which gives you -6 = 7x(2q - p) right?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
cool, now divide both sides by 7(2q - p)
OpenStudy (anonymous):
wait...now i use distributive property...right?
OpenStudy (anonymous):
no keep it inn the brackets its easier
OpenStudy (anonymous):
but, them I would divide -6 by 7(2q-p)
OpenStudy (anonymous):
yeah exactly
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OpenStudy (anonymous):
and you would have x on its own in terms of the variables q and p
OpenStudy (anonymous):
I don't quite get how I would actually divide it by that.
OpenStudy (anonymous):
you dont, you just leave it in that form \[\frac{-6}{7(2q-p)} = x\]
OpenStudy (anonymous):
oh....Can you help me in the other ones? I thought i'd get the hang of it with one
OpenStudy (anonymous):
sure post anotehr here
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