Question

BOYLE'S LAW - MATH EQUATIONS

pV = k
p1V1 = p2v2
Gas = PiVi = PfVf
Initial Pressure = PfVf / Vi
Initial Volume = PfVf / Pi
Pressure = PiVi / Vf
Volume = PiVi / Pf

If a gas has a volume of 1 L at a pressure of 270 kPa, what volume will it have when the pressure is increased to 540 kPa?

In this case, the equation would be: 270(V) = 540. To double the pressure, I must use long division?

270(1)/540
270(540)/1 ?
540(270)/1 ?
540(1)/270 ?

Until somebody actually browses the Chemistry category, I absolutely support my previous indignation that this question belongs in the ma

Answer 1

I am assuming your first equation pV=k, is pressure times volume equals a constant. In which case, plug in the p and V you are initially given to find that constant.

Then for a new pressure, you can use the constant to get the new corresponding volume.

Answer 2

If you are using the second equation, it is 270*1 = 540*v2.

So solving for v2, v2 = 270/540. Long division is perfectly good, although I prefer to reduce to prime factorization..

That is, 270 = 9*3*10
and 540 = 9*3*2*10

So 270/540 is?

Answer 3

\[270 \div 540 = \frac{ 1 }{ 2 }\]

Answer 4

Which is also 50%. In terms of decimals, 0.50

Answer 5

right. cool