Question

CAN SOMEONE PLZ HELP!!

Answer 1

I am not great at these, but I was looking at an odds-and-probability question earlier and found this resource that may help:

http://www.math-magic.com/probability/prob_to_odds.htm

Answer 2

@JakeV8 that didn't really help :(

Answer 3

@JakeV8 but thx for trying!

Answer 4

sorry :(

Answer 5

it's ok. If u know anyone that can help that be great!

Answer 6

What I think you need to do is first convert each lottery "odds" to a probability.

So "1 in 5.2 million" is the odds... need that in the form of a probability.

Answer 7

lol and i do that how?

Answer 8

yeah, well I said I wasn't great at these :)

I think for odds of 1 in 5.2 million, you have a probability of 1 / (5.2 million + 1)

There is 1 winning ticket compared to 5.2 million losing tickets, so in probability terms, there is 1 winner out of (5.2million + 1 total tickets). It's obviously almost the same as the odds, but only because of the large number of tickets... if it was 1 in 3, then the probability would be 1 / (3 + 1) = 1/4

Answer 9

The 2nd lottery had 1 in 805,600 odds... so the probability is 1 / 805601

the probability of winning both lotteries after buying 1 ticket in each is the product of the two individual probabilities...

P = (1/5,200,001) x (1/805,601)

Answer 10

by the time you do all the rounding, you probably can just ignore the +1 on the bottom of each term...

in other words... 1/5.2 million is a good approximation for 1/5,200,001

Answer 11

ok so the answer would be...?

Answer 12

did you lose your calculator? ;)

1/5200001 = 1.92 x 10^(-7)
1/805601 = 1.24 x 10^(-6)

multiply...

2.39 x 10^(-13)

Answer 13

@JakeV8 lol yah actually i did it broke the other day. So which would go 4 a & which for b?

Answer 14

that answer is for (a). We didn't do (b) yet.

Answer 15

so a) is 2.39 x 10^(-13)?

Answer 16

use your computer calculator :) Are you on Windows? On Windows 7, hit the start button, then type "calc" in the search area on the bottom.

Answer 17

yeah, that's (a), but it says round to nearest tenth, which is sort of dumb, since the number is so small. They probably meant to say round to one decimal place, so it might be 2.4 x 10^(-13)

Answer 18

Part b says, you hope to win twice in the 2nd lottery

Prob of winning with ticket 1 = 1/805601 = 1.24 x 10^(-6)
Prob of winning with ticket 2 = 1/805601 = 1.24 x 10^(-6)

Prob of winning with both tickets = Prob1 x Prob2
= 1 / (805,601)^2
= (1.24 x 10^(-6)) * (1.24 x 10^(-6))
= 1.54 x 10^(-12)

rounded, it becomes 1.5 x 10^(-12)

Answer 19

do you get it? I certainly do... I was the one typing it all out... hope you understand how to find probabilities.

It's "# of ways I can win" / "total number of ways"

for two separate events that aren't connected, like the 2 lotteries or even like winning twice in the 2nd lottery, you find the probability of the two events BOTH happening by multiplying their individual probabilities

Answer 20

THX!! would it be creepy if i said i wanna hug u now? lol JK sorta

Answer 21

nah, I know what you mean :)

Glad to help...