Question

Find y" by implicit differentiation

x^4 + y^4 = a^4

4x^3 + 4y^3 y' = 4a^3

y' =(4a^3 - 4x^3)/4y^3

y' = (a^3 -x^2)/y^3

y'' = y^3(3a^2-3x^2)-3y^2(a^3-x^3)/(y^6)

y'' = 3y^2 (ya^2-yx^2-a^3+x^3)/y^6

y'' = (3(ya^2-yx^2-a^3+x^3))/y^4

I showed my work, can someone help me to see if I did anything wrong..