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A circuit has a total resistance of 5 K(omega) and a total voltage of 60V. What is the total current in milliamps?
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Assuming your circuit obeys Ohm's law\[V=IR\]Where V = voltage, I = current, R = resistance, your current will be\[\frac{60}{5}mA=12mA\]
what is the power in the circuit in milliWatts?
Power is defined by\[P=IV=I^2R=\frac{V^2}{R}\]for Ohmic circuits so here it is\[12mA \times 60V= 720 mW\]
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