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Mathematics 5 Online
OpenStudy (anonymous):

How do I solve this question? I will attach a picture

OpenStudy (anonymous):

OpenStudy (shealah):

I am pretty sure that you add the lengths of the sides to equal the hypotenuse and then solve for x...

OpenStudy (anonymous):

3 = 0?

OpenStudy (anonymous):

do like this long side square = sum of ther two sides square ie x2+4x+4=x2+25 so the sides are 5,x(5.25), x+2(7.25)

OpenStudy (shealah):

never mind i think what i was doing was the pythagorean theorem... xD

OpenStudy (anonymous):

well i did the pythagorem theorm, a^2+b^2=c^2, and i got 5^2 + x^2=(x+2)^2 so i then got 25 + x^2=x^2+4x+4 and now i dont kow what to do?

OpenStudy (anonymous):

the Pythagorean theorem is \[a^2 + b^2 = c^2\] so i doubt that :P

OpenStudy (anonymous):

thats exactly what i just wrote.

OpenStudy (anonymous):

but...we need to know two sides lengths to do the Pythagorean theorem and that last comment was to shealah

OpenStudy (anonymous):

yeah I uploaded the picture that has the information

OpenStudy (anonymous):

@TuringTest

OpenStudy (anonymous):

??

OpenStudy (turingtest):

@livethelifewelove is on the right track

OpenStudy (anonymous):

\[25 + x^2 = x^2 +4x + 4\] \[21 = 4x\] \[\frac{ 21 }{ 4 } = x \] \[5 \frac{ 1 }{ 4 }\]

OpenStudy (anonymous):

thats what I got. but it doesnt seem right at all

OpenStudy (turingtest):

well it is

OpenStudy (anonymous):

well ohkay then. Thanks for your help.

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