Look at the figure. Under what conditions will the triangle formed by the three squares be a right triangle? Perimeter of Square 2 is equal to the sum of the perimeters of Square 1 and Square 3. Perimeter of Square 1 is equal to the sum of the perimeters of Square 2 and Square 3. Area of Square 1 is equal to the sum of the area of Square 2 and area of Square 3. Area of Square 2 is equal to the sum of the area of Square 1 and area of Square 3.
Do you know Pythagorean theorem?
well i used to but i forgot
oh yea that
Do you remember how to calculate perimeter of square?
the a square + b square + c square ?
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Can you solve it now?
umm dont know, i don't even know what am suppose to do *sigh
Do you agree that square 1 is the biggest?
yes as i can see
So it has the boggest side lenght, right?
yes
now look at picture on wikipedia. Square 1 is similar to the square with side lenght c.
square 2 to the square with length b and 3 with a.
let say all of them have that side length.
ok
what is then perimeter of square 1?
look am sorry and i know your trying to help me but i just don't know this am sitting here for two hours now and am just so lost and my brain is drained out..
ok
i's c^2
square 2 has perimeter b^2 and square 3 a^2
from Pythagorean theorm c^2=a^2+b^2
so would it be D
Oh. Sorry ive made the mistake. Every time i wrote perimeter i mean area. I'm not an english speaker.
so Area of Square 1 is equal to the sum of the area of Square 2 and area of Square 3
oh ok that's ok
ok thank you, your like the best out every one else right now
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