Question

Geometry help; kinda a story problem (attachment) Plz help! im confused

Answer 1

Vids might help.. thanks! :)
http://www.youtube.com/watch?v=Nr-NnrtTPFI

http://www.youtube.com/watch?v=gKDDoT_BWxk&feature=plcp

Answer 2

use Pythagoras theorem and calculate the distances. compare the distances and check which one is smaller.

Answer 3

Can u plz show me?

Answer 4

in the first problem, and for first option, what is the distance between otters and hyenas ?

what is the distance in x direction and y direction?

Answer 5

Idontknow.. i dont get it :/

Answer 6

okay. what is the distance in x-direction between otters and hyenas??. look in the first attachment.

Answer 7

Well otters coordinates is (1,7) nd hyenas is (3,6)

Answer 8

otters is (-1,7).

Answer 9

Ahh.. yeah.

Answer 10

so, now find out the distances in x-direction and y-direction.

Answer 11

how do u do that?

Answer 12

otters is (-1,7) and hyenas is (3,6), right.

so distance in x-direction = 3 - (-1) = 4
and distance in y-direction = 6-7 = -1

okay?

Answer 13

Yes :) but wat about for the second one?

Answer 14

we are not done with this yet.

Now total distance between otters and rhyenas is = \[\sqrt{4^{2}+(-1)^2}\]=4.12

Answer 15

I see.. but the first one doesnt ask for a # iknow the second one is jaguars to the tigers

Answer 16

similarly find distances for other 3 options and see which one is smaller.

the answer is 'otters and hyenas'.

Answer 17

thanks! so how wuld the second one look like?

Answer 18

second one is also similar.
first find distance between jaguars and tigers. then find distance between tigers and otters and add both. The result would be the total distance.

Answer 19

ugh.. this gives me a headache :/ so it would b.. jaguars is (6, -5) tigers (4, -1) nd otters is (-1, 7)

Answer 20

yes. now find the distance between jaguras and tigers, like we did for the first problem.

Answer 21

6 - 4 = 2 nd -5 - (-1) = -4?

Answer 22

yeah. correct. now, do the sqrt thing.

Answer 23

\[2^{2} and -4^{2} = 4 nd -2?\]

Answer 24

yes find

Answer 25

\[\sqrt{2^{2}+(-4)^2}\]

Answer 26

i get 20?

Answer 27

and apply sqrt.

Answer 28

4.47.. is that right?

Answer 29

yes. thats correct. Now that is the distance between jaguars and tigers.

similarly, now find the distance between tigers and otters.

Answer 30

6+ (-1) = 5 and -5 + 7 = 2

Answer 31

\[\sqrt{5^{2 + 2^{2}}} = 10 + 2 = 12\]

Answer 32

no. tigers is (4, -1) nd otters is (-1, 7)

redo your math.

Answer 33

ugh :/ okk.. 4 + -1 = 3 nd -1 + 7 = 6

Answer 34

\[\sqrt{3^{2 + 6_{2}}}= 6 + 12 = \] ?

Answer 35

18

Answer 36

no dear. you always need to subtract.

Answer 37

so 3^2 = 6 and 6^2 = 12 and subtract that?

Answer 38

No. 4 - (-1) = 5 and -1 - (7) = -8

Answer 39

ohh... then its 5^2 = 10 and -8^2 = 64?

Answer 40

5^2 = ?

Answer 41

25

Answer 42

yaa. so now the distance between tigers and otters would be ?

Answer 43

25 + 64 = 89

Answer 44

and apply sqrt.

Answer 45

9.43

Answer 46

good. now add both the distances.

Answer 47

13.9?

Answer 48

yep. you nailed it. very good.

Answer 49

THANKS!!!!! :D u helped me alot!

Answer 50

Can u help me with one more?

Answer 51

you are welcome. I hope now you can solve any other similar problem.


Yep. Post it.

Answer 52

follow the same procedure as used in the previous problem.

Answer 53

Okk :) so its D = (-1, -3) and E = (0,0) ?

Answer 54

yeah. now find the distance.

Answer 55

-1 + 0 = -1 and -3 + 0 = -3

Answer 56

always do subtract when finding distances.

-1 - 0 = -1 and -3 - 0 = -3.

now find the distance.

Answer 57

-1^2 = 1 and -3^2 = 3

Answer 58

(-3)^2 = ?

Answer 59

9 sorry

Answer 60

yaa. now find the distance.

Answer 61

= 10 and sqrt that right?

Answer 62

yep.

Answer 63

3.16

Answer 64

yeah. answer is $sqrt(10)$. option A.

Answer 65

:)) thanks so much! i dont wanna bug but can u help me with one more. its diffent, its just geometry kick my butt :D if u can I understand

Answer 66

nops. post your Q.

Answer 67

Thanks!

Answer 68

it is also similar question. Here you know distances in horizontal and vertical directions.

so use the same formula.

Answer 69

wat formula?

Answer 70

sqrt(6^2 + 9^2)

Answer 71

36 + 81?

Answer 72

yeah. and sqrt of that.

Answer 73

10.8

Answer 74

yep. Thats correct. very good.

Answer 75

Thanks!!!!

Answer 76

welcome :)