Question

i need help solving equations with radicals

Answer 1

sure

Answer 2

okay whats the first thing i need to do the problem is 3/5+n=-1

Answer 3

you are solving for n?

Answer 4

\[\sqrt{blahblah}\] is a radical right?

Answer 5

yep

Answer 6

nooooooooooo

Answer 7

ohh, you mean quotient like this\[\frac{ blah }{ something }\]

Answer 8

its not blah ._.

Answer 9

:P blah helps me. okay wel you want to get n on its own. so i would subtract the 3/5 from both sides

Answer 10

how its a whole number and its one it would just make it 3/5 again

Answer 11

\[\frac{3}{5} + n = -1\]

Answer 12

2/5?

Answer 13

nevermind it a negative

Answer 14

so it would be -8/5

Answer 15

subtracting 3/5 from both sides

\[n = -1 - \frac{3}{5}\]

Answer 16

yeah

Answer 17

woop woop okay so the answer is -2/5

Answer 18

no, the answer is -8/5

Answer 19

how that doesnt make sense because -3/5+-2/5=1

Answer 20

3/5 + n = -1...... n = -1 - 3/5...... n = -5/5 -3/5....n = -8/5

Answer 21

its negative though

Answer 22

the 1 isnegative you mean?

Answer 23

the 1 and the 3/5 is negative

Answer 24

yes, -1 = -5/5

Answer 25

-5/5 - 3/5 = -8/5 because -5 - 3 = -8

Answer 26

where did 5/5 come from??? and also when you plug 8/5 into the problem its unequal

Answer 27

-8/5 ?

Answer 28

yeah it doesnt work

Answer 29

3/5 -8/5 = -1

Answer 30

noooooooooooooooooooooooo!!!!!!!!!!!! -3/5+n=-1! doesnt that make sense?

Answer 31

\[\frac{3}{5} - \frac{8}{5} = \frac{-5}{5} = -1\]

Answer 32

your formula that you first stated was 3/5 + n = -1

Answer 33

well thats not what i meant

Answer 34

right, what did you mean?

Answer 35

\[\frac{3}{5 + n} = -1\] ?

Answer 36

-3/5+n=-1

Answer 37

right okay

Answer 38

then yep your right, n = 2/5

Answer 39

okay cool thanks bye

Answer 40

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Answer 41

its a telelphone