Question

How could I solve 3x-5y+7, 5x-2y=-1 This is the one question I just cannot get right.

Answer 1

Its a system of equations

Answer 2

You solve for a variable in one of them, and then plug that into the other for whatever variable you solve for

Answer 3

Need me to get you started?

Answer 4

I know how to start it thanks, but I always end up getting some weird result. If you could quickly show the steps that would be great thanks.

Answer 5

So okay, does that mean I can just pick either of the equations and solve for either x or y?

Answer 6

Yes

Answer 7

The first equation doesn't have an equal sign. Is it a typo? Can you correct please?

Answer 8

Sorry, 3x-5y=7

Answer 9

Ah, okay then let's say I pick the second equation to solve first.
Then 5x-2y=-1
x = (2y-1)/5
do you agree?

Answer 10

Yes, I've got that thanks

Answer 11

Then I would use X = to substitute into first eq.
(3/5)(2y-1) -5y =7
Personally, I don't work well with fractions so I would multiply all terms by (5/1)

Answer 12

Then i get 3(2y-) -25y =35

Answer 13

oops typo!
3(2y-1)-25y = 35

Answer 14

Now 6y -3 -25y = 35
Gather like terms solve for y.
-19y = 38

Does that look right?

Answer 15

Thank you, I see where I kept going wrong. Thanks!

Answer 16

No prob-glad to help!