Question

When heated, KClO3 decomposes into KCl and O2. KClO3--> 2KCl+ 3O
If this reaction produced 62.6 g of KCl, how much O2 was produced (in grams)?

Answer 1

theres something wrong with your equation: O wouldn't exist alone, it would exist as O2

Answer 2

2KClO3 --> 2KCl + 3O2
and i know that the KCl is 60.2 g but I don't know how to figure the amount of O in grams

Answer 3

okay so you balanced it

now find out how many moles of KCl you have, then use that to relate it to the number of moles of O2 based on the coefficients

Answer 4

would it be3.23 mol? or would i multiply that by two to get 6.46 since there are two KCl

Answer 5

set up a ratio

\[x mol / 3 O2 = 0.8 mol/ 2 KCl \]

Answer 6

511.3 g of O2?

Answer 7

that number seems a little too high

Answer 8

x= (0.8(3))/2= 1.2 moles

m= n x MW = (1.2mol)(32 g/mol) =38.4 g

Answer 9

sorry that wasn't 302 it was 3 Oxygen2

Answer 10

arent they the same thing?

Answer 11

i think you mistook \[3 O _{2} \] by the number three hundred and two

Answer 12

ohhhh okay. so to determine how much O\[O _{2}\]

Answer 13

what should i do?
if 56.7 g of KCl is produced?

Answer 14

i dont understand how you got the 0.8 earlier

Answer 15

number of moles of KCl = mass KCl / molar mass of KCl

n=m/MW= (62.6 g) / (74.55 g/mol) = 0.8397 moles
(sorry it's 0.84 moles not 0.8 , i didn't have a calculator so i just did it in my head)

Answer 16

if you had 56.7 g

use n=m/MW to get the number of moles

Answer 17

ok so the number of moles is .76 for KCl
now i get the moles for \[O _{2}\]

Answer 18

which would be 31.98, right?

Answer 19

my final answer is 36.48 g of \[O _{2}\]

Answer 20

thats right dude

Answer 21

thanks so much!!!

Answer 22

no prob !

Answer 23

would you mind helping with one more problem? :)