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OpenStudy (nory):
How do I solve a logarithmic equation?
For example, log2 (x+4) + log2 (x) = 5.
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OpenStudy (anonymous):
is that log base 2 ???
OpenStudy (anonymous):
or log base 10 ???
OpenStudy (nory):
Yes. I haven't gotten the hang of the controls yet.
OpenStudy (anonymous):
???
OpenStudy (anonymous):
i will bet base 2
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OpenStudy (anonymous):
is this the problem: \(\large log_2(x+4)+log_2(x)=5 \)
or is it: \(\large log2(x+4)+log2(x)=5 \)
OpenStudy (nory):
It is the former.
OpenStudy (anonymous):
@satellite73 ... ding, ding, ding, ding!!!
OpenStudy (anonymous):
ok... do you know this rule for logs: \(\large log_bM+log_bN=log_b(M\cdot N) \) ???
OpenStudy (nory):
Yes, I do. So I use that rule and then what do I do?
I think I know the answer but I could use a refresher.
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OpenStudy (anonymous):
so you can apply that to the left side of the equation to get :
\(\huge log_2[x(x+4)]=5 \)
we good so far?
OpenStudy (nory):
Yes. I understand. So then I expand x(x+4)?
OpenStudy (anonymous):
yes... but you can do that later...
OpenStudy (anonymous):
do you know how to write this logarithmic equation in exponential form:
\(\large log_{10}(1000)=3 \) ???
OpenStudy (nory):
10 ^ 3 = 1000. Yes. So I write the equation in exponential form?
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OpenStudy (anonymous):
yes.... :)
OpenStudy (anonymous):
wat equation u got now?
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