Question

implicit differentiation help.
http://gyazo.com/9b4fbafd9c4eeb141be754b499a8b4d1

Answer 1

\[y\sin(x^2)=x\sin(y^2)\]
\[y'\sin(x^2)+y\cos(x^2)\times 2x=\sin(y^2)+x\cos(y^2)\times 2yy'\] solve for \(y'\)

Answer 2

it is algebra from here on in

Answer 3

is y'sin(x^2) treated as 1 term or two terms. and 2yy' is one term or two terms?

Answer 4

i am not sure what you mean

Answer 5

sec. can i divide the right hand side by sin(x^2) to get y' alone or do i have to divide by the entire thing, y'sin(x^3)

Answer 6

your job at this point it to get \(y'=\text{something}\)
put everything with \(y'\) on one side of the equal sign, everything else on the other, factor and then divide

Answer 7

\[y'\sin(x^2)+2xy\cos(x^2)=\sin(y^2)+2xy\cos(y^2)y'\]
\[y'\sin(x^2)-2xy\cos(y^2)y'=\sin(y^2)-2xy\cos(x^2)\]
\[(\sin(x^2)-2xy\cos(y^2))y'=\sin(y^2)-2xy\cos(x^2)\] then divide

Answer 8

http://gyazo.com/2c9c550fca9675b08601f48da427bb3f

Answer 9

ty