Question

4cos(theta)=-4sqrt(3) sin(-theta) I am supposed to solve the equation on the interval o(
14 years ago

Answer 1

\[4 \cos (x)=-4 \sqrt{3} \sin (-x)\]
Can be written as
\[4 \cos(x)=4 \sqrt{3} \sin(x) \]

Answer 2

\[4 \cos(x)=4 \sqrt{3} \sin(x)\]
\[\frac{4}{4\sqrt{3}}=\tan(x)\]
\[\frac{1}{\sqrt{3}}=\tan(x)\]

Find the value of tangent
\[x=\tan^{-1}(\frac{1}{\sqrt{3}})=30~degrees\]
Then use the chart, since its positive you look at the positive side, which is 180+x
So, the other x value is
\[x=180+30=210 ~ degrees\]

Answer 3

Converting it to radians
\[\frac{30}{180} \times \pi =\frac{1}{6}\pi\]
\[\frac{210}{180} \times \pi = \frac{7}{6} \pi\]