Question

implicit differentiation help

http://gyazo.com/172d582ad88bc18c73fbf01acb40daf0

Answer 1

\[\sqrt{x+y}-x ^{2}y ^{2}=3\]

Answer 2

\[(\frac{ dy }{ dx })(x+y)^{\frac{ 1 }{ 2 }}-(\frac{ dy }{ dx }) x ^{2}y ^{2}=3(\frac{ dy }{ dx })\]

Answer 3

\[\frac{ 1 }{ 2 }(x+y)^{-\frac{ 1 }{ 2 }}\frac{ dy }{ dx }-x ^{2}2y \frac{ dy }{ dx }+y ^{2}2x=0\]

Answer 4

\[\frac{ dy }{ dx }(\frac{ 1 }{ 2\sqrt{x+y} }-x ^{2}2y)=-y ^{2}2x\]

Answer 5

why did you set equal the equation to 3 at first? :S

Answer 6

because the derivative of 3 is 0

Answer 7

it makes implicit differentiation easier

Answer 8

you should just isolate the scalars scalar quantities

Answer 9

so what is the final answer?

Answer 10

getting there having errors with the program

Answer 11

ok ok

Answer 12

\[\frac{ dy }{ dx }=\frac{ -y ^{2}2x }{ \frac{ 1 }{ 2\sqrt{x+y} } }\]

Answer 13

\[\frac{ dy }{ dx }= -4y ^{2}x\sqrt{x+y}\]

Answer 14

hmm. thanks for taking your time to help me, but i think that answer is wrong. or atleast thats what my site is telling me.

Answer 15

http://gyazo.com/5cf3ba72526e9f75c2e5901c768e6247

Answer 16

ok I'll check it in wolfram alpha and see where I messed up.

Answer 17

going to close this and make another post.

Answer 18

ok can't find how to do implicit differentiation on wolfram

Answer 19

alright no problem. thanks for the help

Answer 20

no problem good luck