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find a value for b so that f is a continuous function for all real numbers. Where f is defined f(x){ x^2 + bx , for x < or = 5 {5sin(pi/2(x)) , for x >5 do i use deriviative here?
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replace \(x\) by 5 in both expressions, set them equal and solve for \(b\) no, you do not need derivatives
\[25+5b=5\sin(\frac{5\pi}{2})\] is a stsart
so would b = -4?
i think -5
25+5b = 5sin(pi/2(5)) 25 + 5b = 5 5b = -20 b= -4?
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