Mathematics
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OpenStudy (anonymous):
determine wether the two lines are parallel, perpendicula, or neither
y=4x+4
y=3-1/4x
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ganeshie8 (ganeshie8):
first, find the slope of each line
OpenStudy (anonymous):
4x nd 3
ganeshie8 (ganeshie8):
slope is just a number
ganeshie8 (ganeshie8):
y = \(\color{red}{4}\)x + 4
ganeshie8 (ganeshie8):
y=3\(\color{red}{-1/4}\)x
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ganeshie8 (ganeshie8):
those are the slopes, becoz the given lines are in form :
y = \(\color{red}{m}\)x + c
where, \(\color{red}{m}\) is the slope
OpenStudy (anonymous):
wich m =3
ganeshie8 (ganeshie8):
no, m is the slope, which is the things attached to 'x'
ganeshie8 (ganeshie8):
not the other one, that we call constant
OpenStudy (anonymous):
-1/4
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ganeshie8 (ganeshie8):
thats right,
so slope of first line = 4
slope of second line = -1/4
ganeshie8 (ganeshie8):
now, multiply both of them
ganeshie8 (ganeshie8):
what u get ?
OpenStudy (anonymous):
-4
ganeshie8 (ganeshie8):
check again
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ganeshie8 (ganeshie8):
product of slopes =
\(4 \times \frac{-1}{4}\)
= ?
OpenStudy (anonymous):
i do u multiply straight across
ganeshie8 (ganeshie8):
\(\cancel{4} \times \frac{-1}{\cancel{4}} \)
= ?
OpenStudy (anonymous):
-1
ganeshie8 (ganeshie8):
thank god ! :)
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ganeshie8 (ganeshie8):
so, we got the product of slopes = -1
OpenStudy (anonymous):
so mean
ganeshie8 (ganeshie8):
that means, both lines are perpendicular
OpenStudy (anonymous):
i mean ur mean i know im slow
ganeshie8 (ganeshie8):
here is the rules :
1) lines are perpendicular if 'product of slopes = -1'
2) lines are parallel if slopes are equal
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ganeshie8 (ganeshie8):
slow is ok, its good coz u see things very clearly when u go slow
OpenStudy (anonymous):
how do u know if its parallel
ganeshie8 (ganeshie8):
u find the slopes, first
if u get both of them equal, then the lines are parallel
OpenStudy (anonymous):
thanks
ganeshie8 (ganeshie8):
np.. yw :) i knw u dont mean it when u said im so mean hehe ;p
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OpenStudy (anonymous):
im serious
ganeshie8 (ganeshie8):
really :'( should i work on fixing it
OpenStudy (anonymous):
its okaay