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Mathematics 15 Online
OpenStudy (anonymous):

Would someone be able to help me with this problem? Based on the meaning of the biconditional, write the negation of P <-> Q

OpenStudy (anonymous):

Note: Your final answer should contain only negations of simple propositions.

OpenStudy (anonymous):

Can you rewrite it as two implications joined by another operator?

OpenStudy (anonymous):

(p->q) and (q->p)

OpenStudy (anonymous):

Now negate the expression: '[ (p->q) and (q->p) ]

OpenStudy (anonymous):

so (-pvq) and (-qVp)

OpenStudy (anonymous):

Well, take it step by step. You just have: '(p->q) V (q->p)

OpenStudy (anonymous):

so -(p->q) v (q->p) then -(-pvq) v (q->p)?

OpenStudy (anonymous):

Yes. And you can also do the same thing for q->p change q->p to 'q v p

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