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Would someone be able to help me with this problem? Based on the meaning of the biconditional, write the negation of P <-> Q
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Note: Your final answer should contain only negations of simple propositions.
Can you rewrite it as two implications joined by another operator?
(p->q) and (q->p)
Now negate the expression: '[ (p->q) and (q->p) ]
so (-pvq) and (-qVp)
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Well, take it step by step. You just have: '(p->q) V (q->p)
so -(p->q) v (q->p) then -(-pvq) v (q->p)?
Yes. And you can also do the same thing for q->p change q->p to 'q v p
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