Question

find the domain 1/4^square root of x^2-5x .. is the answer (-infinity, -1/2 closed bracket ???

Answer 1

\[(- \infty,0] \]

Answer 2

for x>o it is not defined

Answer 3

the thing inside radical must be >= 0

Answer 4

solve this :

x^2-5x >= 0

Answer 5

is 0 included ?? if we substitiue o in terms of x we get a negative answer. so its wrong right??

Answer 6

answer will also be 0

Answer 7

you need to solve that inequality, and see what u get as solution :)

Answer 8

can you solve it for me ? ^_^ i suck at calculus

Answer 9

hmm two ways we can solve,

u familiar wid parabola ?

Answer 10

graph of parabola

Answer 11

nope

Answer 12

ok, then factor that inequality, and check the range of solutions

Answer 13

x^2-5x >= 0

factoring we get,

x(x-5) >=0
(x-0)(x-5) >= 0

Answer 14

now the critical points are 0 and 5, lets see in what range the inequality is TRUE

Answer 15

pick a value between 0 and 5,

Answer 16

2

Answer 17

test the inequality at x = 2

Answer 18

x(x-5) >= 0
2(2-5)
2(-3)
-6

its not greater than 0, FALSE !