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OpenStudy (shubhamsrg):
5x = 2x+ 9 simply..isnt it ?
OpenStudy (anonymous):
\[5x=2x+9\]
OpenStudy (anonymous):
5x-2x=9
3x=9
x=3
OpenStudy (anonymous):
Simple.
OpenStudy (4meisu):
You would disregard the logs..?
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OpenStudy (anonymous):
actually, you should tak Anti log both the side. so it will ultimately 2 simple equation. as I explained already.
OpenStudy (kropot72):
@4meisu If log A = log B, then A = B
OpenStudy (lgbasallote):
unless 5 was the base...
OpenStudy (lgbasallote):
that's a different story
OpenStudy (linknissan):
u can only discard if the base of the log is the same..here the base of both the log in 10..tht is default
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OpenStudy (kropot72):
@lgbasallote Please clarify why the deduction "If log A = log B, then A = B" is not true for any base of the logs (with the condition that the same base is used on each side of the equation).
OpenStudy (lgbasallote):
i was referring to the question
OpenStudy (linknissan):
this is true if the base of the logs r same..hn A=B..or else not
OpenStudy (lgbasallote):
could have just been copy-pasted thus failed to show that 5 is the base
OpenStudy (lgbasallote):
the question could have been this \[\huge \log_5 x = \log (2x+9)\]
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OpenStudy (kropot72):
@lgbasallote You are right. The original question could well have been as you point out.