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Mathematics 14 Online
OpenStudy (4meisu):

Solve log5x = log (2x+9)

OpenStudy (shubhamsrg):

5x = 2x+ 9 simply..isnt it ?

OpenStudy (anonymous):

\[5x=2x+9\]

OpenStudy (anonymous):

5x-2x=9 3x=9 x=3

OpenStudy (anonymous):

Simple.

OpenStudy (4meisu):

You would disregard the logs..?

OpenStudy (anonymous):

actually, you should tak Anti log both the side. so it will ultimately 2 simple equation. as I explained already.

OpenStudy (kropot72):

@4meisu If log A = log B, then A = B

OpenStudy (lgbasallote):

unless 5 was the base...

OpenStudy (lgbasallote):

that's a different story

OpenStudy (linknissan):

u can only discard if the base of the log is the same..here the base of both the log in 10..tht is default

OpenStudy (kropot72):

@lgbasallote Please clarify why the deduction "If log A = log B, then A = B" is not true for any base of the logs (with the condition that the same base is used on each side of the equation).

OpenStudy (lgbasallote):

i was referring to the question

OpenStudy (linknissan):

this is true if the base of the logs r same..hn A=B..or else not

OpenStudy (lgbasallote):

could have just been copy-pasted thus failed to show that 5 is the base

OpenStudy (lgbasallote):

the question could have been this \[\huge \log_5 x = \log (2x+9)\]

OpenStudy (kropot72):

@lgbasallote You are right. The original question could well have been as you point out.

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