A block of wood of length 40cm and area of cross section 15cm^2 floats in water with 3/8 of its length above water.What is the density of wood? (Density of water=1g/cm^3) a) 0.256g/cm^3 b)0.526g/cm^3 c)0.625g/cm^3 d)0.650g/cm^3
@UnkleRhaukus @sauravshakya @Coolsector @hartnn @.Sam. @bahrom7893
@estudier @aroub
@ganeshie8 @Yahoo!
buoyancy force will be 15 * (5 * 40 / 8) * 1 * 9.8 upwards .. now we have gravitational force Mg we can change Mg into (densityWood) * (volumeWood) * 9.8 so Mg is (densityWood) * 40 * 15 * 9.8 now Mg and buoyancy are equal since the wood stands still : densityWood * 40 * 15 * 9.8 = 15 * 25 * 9.8 densityWood = 0.625
sorry for all the corrections .
you should read it all over again since i corrected stuff at the first line as well
@Coolsector I guess buoyancy force will be 15 * (3 * 40 / 8) * 1 * 9.8 ^ Check this
@sauravshakya with 3/8 of its length above water ABOVE WATER
use formula v1.d1.g= v2. d2.g
You do not need gravity to solve this problem. If an object sinks: volume of object = volume of (displaced) water If an object floats: mass of object = mass of (displaced) water
obviously..but this will help dude to get insight of full fromula
@hartnn @sauravshakya @Yahoo!
i don't understand
So, u didnt get what @coolsector did?
no
plz tell me
Upthrust = weight of displaced liquid
U know that?
yaa
And when a body floats the weight of the body is equal to the upthrust
right?
right
Thus, weight of the object=weight of displaced liquid Mass of the object=mass of displaced liquid density*volume of object=density*volume of displaced liquid density*40*15 = 1* 5/8 *40 *15
Now, simplify it.
375
it gets 375
Nope it is 5/8
howz
Are u serious??????? Just do simple algebra.
\[1\times \times \frac{5}{8}\times40\times15\]
I know u can do it.
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