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Mathematics 18 Online
OpenStudy (anonymous):

graph each equation. is it a function? A. x=1 B. x=0 I saw the example but its werid..

OpenStudy (anonymous):

it will be a line so give it a try

OpenStudy (anonymous):

Huh like idk what to do with numbers or how to do on graph

OpenStudy (anonymous):

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OpenStudy (anonymous):

okay.

OpenStudy (anonymous):

then what

OpenStudy (anonymous):

actual eq. of line ax+by=c so in this if we put y=0 we find both line

OpenStudy (anonymous):

it is not a function, because it is not one to one. Meaning that for it to be a function there needs to be a relationship such that for every x there is only one y. In this case, there are many y possibilities for 1 x. http://www.purplemath.com/modules/fcns.htm

OpenStudy (anonymous):

i think it simple for understanding

OpenStudy (anonymous):

\(x=1\) means "x is always 1, no matter what \(y\) is" so all the points on the graph have a 1 as the first coordinate the \(y\) can be any number so you can have \((1,2), (1,1), (1,2), (1,3),\) etc

OpenStudy (anonymous):

lorda mercy "one to one" is a completely separate concept from "is it a function"

OpenStudy (anonymous):

it is a vertical like it does not pass the "vertical line test" because both the points \((1,2)\) and \((1,3)\) are on the graph, it is not a function repeated \(x\) values means not a function

OpenStudy (anonymous):

first you are not stupid, you are just not trying

OpenStudy (anonymous):

no it is neither stupidity nor lack of trying "functions' is a hard concept

OpenStudy (anonymous):

every line is a function, except a vertical line any other line will determine a function

OpenStudy (anonymous):

well I suppose you can look at it that way, but one to one and the meaning of a function is the same in my head.

OpenStudy (anonymous):

i still dont get it. -.-

OpenStudy (anonymous):

x = 1 and x = 0 are two different vertical lines that have infinitely many y possibilities

OpenStudy (anonymous):

slow we have \(x=1\) is \((1,3)\) on the graph? yes, because \(x=1\) is \(1,2)\) on the graph"? yes, because \(x\) is still 1

OpenStudy (anonymous):

how about \((1,7)\)? yes, that is on the graph also the graph is a vertical line

OpenStudy (anonymous):

now why isn't it a function? because for a function, the first coordinate cannot repeat

OpenStudy (anonymous):

so if you have a graph with two points with the same first coordinate, it is not a function

OpenStudy (anonymous):

what do you mean the first coordinate cant repeat?

OpenStudy (anonymous):

like 1,1?

OpenStudy (anonymous):

ok for \((1,3)\) the first coordinate is 1

OpenStudy (anonymous):

(x,y) x being the first coordinate

OpenStudy (anonymous):

for \((1,2)\) the first coordinate is 1

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

so if i see both points \((1,3)\) and \((1,2)\) the first coordinate is repeated

OpenStudy (anonymous):

of course its repeated x=1

OpenStudy (anonymous):

right

OpenStudy (anonymous):

so, where are you lost? what doesnt make sense

OpenStudy (anonymous):

what does?

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