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OpenStudy (anonymous):
Find the derivative of f when
f(x) = 2 tan(x) + 3 cot(x)
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OpenStudy (cwrw238):
derivative of tan x is sec^x
can't remember derivative of cot x - try googling it
first term of derivative is 2 sec^2 x
OpenStudy (anonymous):
of cotx? its -csc^2
OpenStudy (anonymous):
please help
OpenStudy (anonymous):
sol: let y=f(x)
y=2tan(x)+3cot(x)
=2dy/dxtanx+3dy/dxcotx
=2*sec^2x+3*-cosec^2x
=2sec^2x-3cosec^2x
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OpenStudy (cwrw238):
oh ok
so f'(x) = 2 sec^2 x - 3 csc^2 x
OpenStudy (anonymous):
think they want me to make in ration form its number 3 on the hw i have attached
OpenStudy (anonymous):
is it answer??
OpenStudy (anonymous):
thats not one of the answer choices
OpenStudy (anonymous):
muhammand please help
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OpenStudy (anonymous):
estudier please help
OpenStudy (anonymous):
are these questions???
OpenStudy (anonymous):
yes the document i have attached is the homework i am looking at number 3 specifically
OpenStudy (cwrw238):
ah what they have done is convert the sec and csc to sin and cos
OpenStudy (anonymous):
okay...
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OpenStudy (anonymous):
so what is the answer
OpenStudy (cwrw238):
2 sec^2 x - 3 csc^2 x
= 2 * 1/cos^2 x - 3 * 1 / sin^2 x
OpenStudy (cwrw238):
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