An arrow is shot from a now at an angle of 35 degrees above the horizontal with an initial speed of 50. m/s. what are the arrow's horizontal (x) and vertical (y) components? (use trig. to answer)

Question

anonymous · Answer

horizontal component: velocity x cosine of angle.
Vertical component: = Velocity x sine of angle

anonymous · Answer

tbh the sine and cosine are extremely confusing to me ive been over them many times and still dont under stand them.... how would i end up working out that problem?

anonymous · Answer

the component along the line which is a part of the angle is always a multiple of cosine, the other one sine

anonymous · Answer

so then woul dit be 50cos(35) which would equal -45.1846 and 50sin(35) which would equal -21.4091?

anonymous · Answer

it is 40.95 and 28.67 not in negative

anonymous · Answer

oh okay thanks ^_^

anonymous · Answer

:-)