Question

how do you find the derivative of f(x)=xsinx+1/cosx?

Answer 1

Can you put some parentheses on the right-hand side? It's ambiguous.

Answer 2

NoelGreco is right, you gotta clarify that

Answer 3

If you mean (xsinx+1)/cosx,then use the rule of divide to get ((cosx)(xcosx+sinx)-(xsinx+1)(-sinx))/(cosx)^2
If you mean xsinx+ 1/cosx,then,find the derivative seperately.Namely,(xcosx+sinx)+secxtanx

Answer 4

product rule for the first part and quotient for the second

Answer 5

\[\frac{ x }{ \cos ^{2}(x) } + tanx (\frac{ \cos x -1}{ \cos x } )\]

Answer 6

sinx+cosx-(sinx/cos^2x)

Answer 7

hmmmm... first use product rule for xsinx...
then 1/cosx = secx.... find derivative of secx..
job done