Question

During a treasure hunt, cody walks 45.0 m south and 7.50 m to the west. what single straight line displacement could cody have taken to reach the treasure? (remember that magnitude and angle and direction are all needed for your answer.)

Answer 1

here is what i have so far

Answer 2

use pythagoren theorem. square of hypontaneous ( in this case displacement) is equal to the sum of square of sides.

Answer 3

45.62 meter approx

Answer 4

\[ac ^{2}= ab ^{2}+bc ^{2}\]

Answer 5

but you also need the angle, therefore using trigonometry
To find this angle you would use tan
tan\[\tan \theta = \frac{ opposite }{ adjacent }\]
hence, \[\theta = \tan^{-1} \left( \frac{ 7.5 }{ 45 } \right)\]
= 9.46
= south 9.46 west
or 189.46 degrees (due north)