Find the interest rate needed for an investment of 24000 dollars to grow to an amount of 34300 dollars in 8 years if the interest is compounded monthly.
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OpenStudy (cwrw238):
sorry - i got called away
formula is 34,300 = 24,000( 1 + r / 12)^(8*12)
you have to solve this for r
OpenStudy (cwrw238):
can u continue?
OpenStudy (lin.ivory):
thats ok! thanks!
I put 34300/24000 = (\[(1+ \frac{ r }{ 12 })^(96)\]
OpenStudy (lin.ivory):
to the power of 96
OpenStudy (lin.ivory):
but i dont know how to log both side? or get rid of the exponent 96
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OpenStudy (cwrw238):
yes thats right
OpenStudy (cwrw238):
ok take logs of both sides
ln (34300/24000) = 96 * ln (1 + r/12)
OpenStudy (cwrw238):
r will be in decimal form
OpenStudy (lin.ivory):
sorry but is it possible for you to explain ln? i dont quite understand the concept
OpenStudy (cwrw238):
wait we can do this another way not involving logs
34300/24000 = (1 + r/12)^ 96
(1 + r/12) = (34300/24000)^(1/96)
ur calculator should be able to do this
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OpenStudy (lin.ivory):
but the answer came out wrong?
OpenStudy (cwrw238):
i got 0.047 - or near that id have to do it again
what did you get?
OpenStudy (cwrw238):
0.0447 or 4.47 %
OpenStudy (lin.ivory):
OOOooops!! i typed in the wrong decimal lol!
OpenStudy (cwrw238):
haha - we all do that sometimes
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