Two trains leave the depot at the same time, one traveling east and the other traveling west. The speed of one train is 7 mph slower than the other. If after 5 hours the distance between the trains is 175 miles, find the speed of each train.
asuming that both have 0 acceleration and constant velocity
\[s_x=v_0 t+s_0\] \[v=v_0\]
since we're assuming that the station is at (0,0)
so if we're given that velocity of one train is slower than than the other \[v_{t1}=v_0=v_{t2}-7\]
and \[v_t\] is just itself
\[s_x=\] the addition of both displacement equations sooo \[175=(v-7)t+vt\]
\[175=(v_{t2}-7)(5)+v_{t2}(5)\] \[175=5v_{t2}-35+5v_{t2}\] \[210=10v_{t2}\] \[21mph=v_{t2}\] since we know \[v_{t1}=v_{t2}-7\] \[v_{t1}=21-7=14mph\]
lastly check to make sure
the distance of train 1 would be \[s_{t1_{x}}=v_{t1}t=14(5)=70miles\]
\[s_{t2_{x}}=v_{t2}t=21(5)=105miles\] 105+70 = 175
answers are one train at 14 mph and the other at 21 mph
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