Mathematics
6 Online
OpenStudy (anonymous):
multiply the write answer without the exponents
(12x10^5)x(3x10^6)
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jimthompson5910 (jim_thompson5910):
12 * 3 = ???
OpenStudy (anonymous):
i have a answer but idk if it is write
jimthompson5910 (jim_thompson5910):
ok show me
OpenStudy (anonymous):
2 multiply by 3=6
10^5 and 10^6= 10^1
so 6x10^1=0.06
jimthompson5910 (jim_thompson5910):
not quite
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jimthompson5910 (jim_thompson5910):
what is 12 times 3 ?
OpenStudy (anonymous):
36
jimthompson5910 (jim_thompson5910):
What is 10^5 times 10^6 ?
OpenStudy (anonymous):
im sorry its (2x10^5)
OpenStudy (anonymous):
i typed too fast
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jimthompson5910 (jim_thompson5910):
rewrite the whole problem again
OpenStudy (anonymous):
ok (2x10^5) x (3x10^6)
jimthompson5910 (jim_thompson5910):
so 2 * 3 = 6, good so far
jimthompson5910 (jim_thompson5910):
10^5 times 10^6 = ???
OpenStudy (anonymous):
10^1
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jimthompson5910 (jim_thompson5910):
no
OpenStudy (anonymous):
5-6
jimthompson5910 (jim_thompson5910):
you add the exponents
jimthompson5910 (jim_thompson5910):
5+6 = 11, so
10^5 times 10^6 = 10^11
OpenStudy (anonymous):
6x10^11=
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jimthompson5910 (jim_thompson5910):
so the product (2x10^5) x (3x10^6) becomes 6 x 10^11
jimthompson5910 (jim_thompson5910):
now write that in standard form
jimthompson5910 (jim_thompson5910):
basically, you would write 11 zeros after the '6'
OpenStudy (anonymous):
60^11
jimthompson5910 (jim_thompson5910):
no
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jimthompson5910 (jim_thompson5910):
6 x 10^11 = 600,000,000,000
This is the number 600 billion
OpenStudy (anonymous):
so i had a similar problem to that and i had to subtract the exponents
jimthompson5910 (jim_thompson5910):
when you divide, yes, you subtract the exponents
jimthompson5910 (jim_thompson5910):
but this time you're multiplying, so you add the exponents
OpenStudy (anonymous):
oh thats y
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jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
and i kept putting 0.06... ok i have another question
jimthompson5910 (jim_thompson5910):
ok you can ask one more
OpenStudy (anonymous):
simplify (6a)^-2
OpenStudy (anonymous):
i was wondering do i multiply 6x6=
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jimthompson5910 (jim_thompson5910):
yes, that's one of the steps, but not yet though
jimthompson5910 (jim_thompson5910):
when you have a negative exponent, you can use this idea
x^(-k) = 1/(x^k)
where k is any positive number
jimthompson5910 (jim_thompson5910):
so for example,
x^(-2) = 1/(x^2)
jimthompson5910 (jim_thompson5910):
this means that
(6a)^(-2) = 1/( (6a)^2 )
OpenStudy (anonymous):
ok im viewing
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jimthompson5910 (jim_thompson5910):
now square 6a, what do you get
OpenStudy (anonymous):
ok i get 36a
jimthompson5910 (jim_thompson5910):
close
jimthompson5910 (jim_thompson5910):
a*a = ???
OpenStudy (anonymous):
im not sure 6x6=36
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jimthompson5910 (jim_thompson5910):
good, so
a times a = a^2
jimthompson5910 (jim_thompson5910):
which means (6a)^2 = 36a^2
jimthompson5910 (jim_thompson5910):
and that
(6a)^(-2) = 1/( 36a^2 )
OpenStudy (anonymous):
so 36a^2 as the answer
jimthompson5910 (jim_thompson5910):
1 over 36a^2
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jimthompson5910 (jim_thompson5910):
36a^2 is the entire denominator
OpenStudy (anonymous):
1/36a^2
jimthompson5910 (jim_thompson5910):
yes
\[\Large \frac{1}{36a^2}\]
OpenStudy (anonymous):
oh ok well its another similar to that but different
jimthompson5910 (jim_thompson5910):
i gotcha
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OpenStudy (anonymous):
it says (-6p)^4
jimthompson5910 (jim_thompson5910):
that's similar, but there's no negative exponent
jimthompson5910 (jim_thompson5910):
so you won't have a fraction
OpenStudy (anonymous):
i have 1296p
jimthompson5910 (jim_thompson5910):
it should be 1296p^4
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jimthompson5910 (jim_thompson5910):
since you also raise p to the 4th power
OpenStudy (anonymous):
oh ell you c im trying
OpenStudy (anonymous):
i thank u
jimthompson5910 (jim_thompson5910):
np
OpenStudy (anonymous):
do you have time for one more to see if im correct?
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OpenStudy (anonymous):
hello