Question

Determine whether the series is convergent or divergent. If it is convergent, find its sum.

Problem inside.

Answer 1

\[\sum_{2}^{\infty} \frac{ k^{2} }{ k^{2}-1}\]

Answer 2

Actually, that should be k = 2 under the summation.

Answer 3

Basically, I know that the answer converges, but I don't know why. I would think that if the numerator was infinity squared and the denominator was infinity squared minus one, that the numerator was approaching infinity at a faster rate, thus making it diverge because it could just get bigger and bigger. But I guess that's incorrect reasoning.

Answer 4

Secondly, I'm trying to put it into Ar ^ n format to begin to find the sum. I tried using k^2 times (k^2 - 1) ^-1 but I'm not sure if that's correct either.