Question

Find y" in terms of x and y by implicit differentiation. x^3+y^3=4^3.
So far I have found the first derivative which is 3x^2+3y^2(dy/dx) = 0 and I know that when you solve for dy/dx you get -x^2/y^2 and then you plug that into the first derivative to take the second so it would look like this when you plug it into the first derivative 3x^2+3y^2(-x^2/y^2). But now I am stuck

Answer 1

is that 4^3?