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Mathematics 67 Online
OpenStudy (anonymous):

Find y" in terms of x and y by implicit differentiation. x^3+y^3=4^3. So far I have found the first derivative which is 3x^2+3y^2(dy/dx) = 0 and I know that when you solve for dy/dx you get -x^2/y^2 and then you plug that into the first derivative to take the second so it would look like this when you plug it into the first derivative 3x^2+3y^2(-x^2/y^2). But now I am stuck

OpenStudy (precal):

is that 4^3?

OpenStudy (precal):

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