The sum of nine consecutive integers; n = first integer of the nine
If n is the first, then what does the ninth term look like?
not sure
They are consecutive integers, so they come one right after the last.
i know for if its the 8 term the answer would be 8n+28
(In the language of arithmetic sequences, the common difference is 1).
consecutive integers are n , n+1, N+2
Well, there's only nine of them, so let's list them all out and look, eh? n, n+1, n+2, n+3, n+4, n+5, n+6, n+7, n+8
yeah
So there are nine n's and the series 1+2+3+4+5+6+7+8.
Notice in the series, 1+2+...+8 that the first and last terms add up to the same number, 9, that the second and second-to-last add up to, and so on.
So there are four pairs of numbers that add up to 9.
like 4 and 5?
Those too, yep.
how would the equation look like for this question?
Well, like we saw, there are 9n and 4 groups of 9 make 36, so S=9n+36
oh i see
thanks
No prob' Try a couple more similar examples and think through the reasoning that I showed you until you see how it all fits together.
yes i shall do that
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