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Mathematics 8 Online
OpenStudy (anonymous):

The sum of nine consecutive integers; n = first integer of the nine

OpenStudy (anonymous):

If n is the first, then what does the ninth term look like?

OpenStudy (anonymous):

not sure

OpenStudy (anonymous):

They are consecutive integers, so they come one right after the last.

OpenStudy (anonymous):

i know for if its the 8 term the answer would be 8n+28

OpenStudy (anonymous):

(In the language of arithmetic sequences, the common difference is 1).

OpenStudy (anonymous):

consecutive integers are n , n+1, N+2

OpenStudy (anonymous):

Well, there's only nine of them, so let's list them all out and look, eh? n, n+1, n+2, n+3, n+4, n+5, n+6, n+7, n+8

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

So there are nine n's and the series 1+2+3+4+5+6+7+8.

OpenStudy (anonymous):

Notice in the series, 1+2+...+8 that the first and last terms add up to the same number, 9, that the second and second-to-last add up to, and so on.

OpenStudy (anonymous):

So there are four pairs of numbers that add up to 9.

OpenStudy (anonymous):

like 4 and 5?

OpenStudy (anonymous):

Those too, yep.

OpenStudy (anonymous):

how would the equation look like for this question?

OpenStudy (anonymous):

Well, like we saw, there are 9n and 4 groups of 9 make 36, so S=9n+36

OpenStudy (anonymous):

oh i see

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

No prob' Try a couple more similar examples and think through the reasoning that I showed you until you see how it all fits together.

OpenStudy (anonymous):

yes i shall do that

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