Question

implicit differentiation help.
Somebody here has got to know how to do this problem... >.<

http://gyazo.com/53dfb49c3ca8d1a3b949b4f9f2afa67c

Answer 1

Do you know the power rule?

Answer 2

yes

Answer 3

i know how to get y' alone. im having problems putting it in the formular y-y1=m(x-x1)

Answer 4

How so?

Answer 5

(2/3) * x^-(1/3) + (2/3) * y^-(1/3) * (dy/dx) = 0

dy/dx = -x^(-1/3) / y^(-1/3)

Answer 6

yes, got that far. now what coolsector?

Answer 7

Fill in y

Answer 8

and x

Answer 9

plug x = -3sqrt(3) , y= 1

Answer 10

i filled in both x and y. and got a number. i used that as my slope in the equation y-y1=m(x-x1)

Answer 11

you get
dy/dx = - (3sqrt(3))^(-1/3)

Answer 12

yes, which is -1.732 corect?

Answer 13

mm i ges -0.577 in fact

Answer 14

and x1 = -3sqrt(3) y1 = 1...

Answer 15

dy/dx = -x^(-1/3) / y^(-1/3)

i replaced x and y with given points in this, and got -1.732

Answer 16

dy/dx = -(3sqrt(3))^(-1/3) / 1

Answer 17

dy/dx = -(3sqrt(3))^(-1/3) i get -0.577

Answer 18

ok. go on with that then. what is the final answer?

Answer 19

need an equation in y= form

Answer 20

y =1 -0.577(x+3sqrt(3))
y= 1 -0.577x -3
y = -0.577x -2

Answer 21

in fact dy/dx = -1/sqrt(3)

so :
y = -x/sqrt(3) -2

Answer 22

\[y = \frac{ -x }{ \sqrt{3} } -2\]

Answer 23

http://gyazo.com/b7dc43e97670c3b7879e2ed74d7c4fe0

Answer 24

says incorrect :/

Answer 25

if we plug x = -3sqrt(3) we get y = 1 right ?

Answer 26

yes

Answer 27

well weird

Answer 28

yeah, i have no idea how to do this problem :/ thanks anyways

Answer 29

im sure it is correct

Answer 30

just tried putting in again, says wrong. :|

Answer 31

going to close post and make another one.