Question

Someone PLEASE help. I have been trying to get someone to help me with this for the past hour.
See attached picture

Answer 1

\[-\frac{2xy^2+2xy\frac{x^2}{y^2}}{y^4}\] right? we can do it

Answer 2

you get
\[-\frac{2xy^2+\frac{2x^3}{y}}{y^4}\] as a first step, then if you multiply top and bottom by \(y\) to clear the fraction you get
\[-\frac{2xy^3+2x^2}{y^5}\]

Answer 3

oh damn i made a mistake hold on

Answer 4

my stupid exponent is wrong on the last \(x\) term sorry
\[-\frac{2xy^3+2x^4}{y^5}\]

Answer 5

okay so then you can factor out a two on the top right to get 2(xy^3+x^4)/y^5 correct?

Answer 6

if you want to be fancy and factor, why not factor out \(2x\)?

Answer 7

so then when you do that you get 2x(x^3+y^3)/y^5 and because x^3+y^3=64 from the original equation I can substitute that in to get 2x64/y^5 correct?

Answer 8

The answer I put in isn't correct according to my homework? what did I do wrong?

Answer 9

if you factor out the \(2x\) you get
\[-\frac{2x(y^3+x^3)}{y^5}\]

Answer 10

and guess what??

Answer 11

What?

Answer 12

\[x^3+y^3=64\]!!

Answer 13

oh, i see, you did that
hmmm

Answer 14

did you type in
\[-\frac{128x}{y^5}\]?

Answer 15

Sadly I tried that too :(

Answer 16

damn, i am almost positive it is right. give me a second to start from the beginning

Answer 17

no i get the same damn thing again
\[-\frac{128x}{y^5}\]

Answer 18

sorry, i don't have a better suggestion

Answer 19

Thank you for your help

Answer 20

you did type in the minus sign right?

Answer 21

Yes

Answer 22

then i am lost, but i am \(99\tfrac{44}{100}\%\) sure it is right. in fact i have seen this exact problem before, it is rather common

Answer 23

Okay. Thanks.