Mathematics
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OpenStudy (anonymous):
Find second derivative of the function
r={1+4theta / 4theta} (4-theta)
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OpenStudy (anonymous):
\[r = \frac{1 + 4\theta}{4\theta} \times(4-\theta)\] ?
OpenStudy (anonymous):
yes, how to do second derivative please
OpenStudy (anonymous):
sure, you just take the derivative, then take it again on the derivative. you know how to thake the derivative of this fucntion r?
OpenStudy (anonymous):
No, I'm confused when it's quotient function, can you help
OpenStudy (anonymous):
sure, the easiest thing to do here would be to multiply by the 4 - theta first
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OpenStudy (anonymous):
do that and type what you get in the equation editor
OpenStudy (anonymous):
simplify it as much as possible
OpenStudy (anonymous):
can you show it here so I can see?
OpenStudy (anonymous):
\[\frac{d}{dx}( \frac{g(x)}{f(x)}) = \frac{g(x)'f(x) - f(x)g(x)'}{f(x)^2}\]
OpenStudy (anonymous):
so what is g(x) for you?
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OpenStudy (anonymous):
1+4theta rigt?
OpenStudy (anonymous):
no, simplify the equation first
OpenStudy (anonymous):
multiply 1 +4theta by (4 - theta)
OpenStudy (anonymous):
then you will just have r = somthing/something
OpenStudy (anonymous):
differentiate using the rule i gave you up there^
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OpenStudy (anonymous):
oh ic, much better
OpenStudy (anonymous):
another question??
OpenStudy (anonymous):
go on
OpenStudy (anonymous):
give me few minutes as I'm trying to solve for this problem, thanks
OpenStudy (anonymous):
well im going to go now. Good luck!
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OpenStudy (anonymous):
thanks for your help