A virtual cookie for anyone that can help me!
Calc 2 stuff: lim as x-infinity of the square root of (x^2 + 6x) minus x...so basically the x^2 + 6x is under the radicand and minus x is outside

Question

A virtual cookie for anyone that can help me!
Calc 2 stuff: lim as x->infinity of the square root of (x^2 + 6x) minus x...so basically the x^2 + 6x is under the radicand and minus x is outside

calculusfunctions · Answer

$$\lim_{x \rightarrow \infty}(\sqrt{x ^{2}+6x}-x)$$First you should realize that the denominator is one. Right?

anonymous · Answer

denominator is 1 yes

calculusfunctions · Answer

Now rationalize the numerator. @Sidhantb5, do you know how to do that?

anonymous · Answer

i might, i just need a push

calculusfunctions · Answer

In other words, multiply the numerator and the denominator by the conjugate of the numerator. Do you know what I'm talking about?

anonymous · Answer

so a fancy form of #1? like root (X^2-6x)/ the same?

fellowroot · Answer

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