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Find d(2)y|d(2)x in terms of x and y. y^2=x^3 For y' I got: 2yy'=3x^2 y'(2y)=3x^2 y'=3x^2/2y I would use the quotient rule for y'', right? My text book is doing something totally different :(
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u can use product rule here also y'(2y)=3x^2
your book attempted to simplify y' using y^2=x^3
With the use of the product rule would I rewrite the fraction \[\frac{ 3x^3 }{ 2y }\] as \[(3x^3) 2y^-\]
i was talking about this : y'(2y)=3x^2 diff. w.r.t x y''(2y)+2y'y' = 6x <----product rule
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Haha! Ohh! I see now! Thanks!
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