Question

how to find log of log50/15?

Answer 1

@lgbasallote @Hero @Libniz @TranceNova

Answer 2

is it (log 50)/15 or log(50/15) ?

Answer 3

\[\log_{50/15} \]

Answer 4

that has no meaning
the base is 50/15 ?

Answer 5

convert 50=5*10
and 15=5*3
so now =log10/3
=log10-log3
=1-log3

Answer 6

now it easily solving i think

Answer 7

lol, no...and she also needs to find log of that.....

Answer 8

waht shold be the value of = -2.303*2*298*log50/15 ?
now please elaboarate.

Answer 9

i think -717.69

Answer 10

can't u use calculator ?
u can find log (50/15) = log(10/3) using calcy

Answer 11

@ruchi k now can i ask 1 que.?

Answer 12

* log(10/3) using calcy ONLY, not manually

Answer 13

yah @vipul92
hey @hartnn btw the value is -1436 calories.

Answer 14

@hartnn it's ok @vipul92 is just posting answers to people's posts and usually posting wrong answers

Answer 15

-1436 is double the value of expression that u wrote

Answer 16

hey @gaara you don't know how to multiply and subtract two no. and said that i m wrong

Answer 17

excuse me.! @vipul92 this place is for posting questings and answering them, so please don't do useless talks here.
that would go against the code of conduct!
thanks!

Answer 18

k as u wish

Answer 19

using calculator -2.303*2*298*log(50/15) = -717.697
-1436 is double of that

Answer 20

sorry to everone the question is something like this : -2.303*2*2*298*log(50/15) =

Answer 21

-2.303*2*2*298*log(50/15)=-1436 using calculator

Answer 22

hey i'm asking that how u hav find log in this question

Answer 23

doesn't your calculator have the option to calculate log?
if not then u can simplify log(50/15) = log (10/3) = log 10 -log 3 =1-log 3
and u need to know log 3 = 0.477

Answer 24

in xamination calculator r nt preferred.

Answer 25

then i think, u need to remember atleast these 2 :
log 2 = 0.301, log 3 = 0.477

Answer 26

hey hw to find log of 20/5?

Answer 27

I'm still trying to figure out the notation. What country are you from?

Answer 28

You can interpret that in different ways:

\[\log_{20}{(5)}\]
\[\log_{10}(20/5)\]
\[\log_{5}(20)\]

Answer 29

If it's

\[\log_{10}(20/5) = \log_{10}(4)\] , then it is relatively easy.

Answer 30

But if it's something other than that, then idk

Answer 31

@ruchi.

Answer 32

If you want help, you will need to clarify what the notation is.

Answer 33

Okay, so if it is what I think it is, then

log(20/5) = 2 log(2) = .602

Answer 34

hey hw u fing it?

Answer 35

\(\log (20/5)=log 4 = log (2^2)=2log2 \\ \text{from the property of log that :} \\ \huge logx^n=nlogx\)
and as i mentioned, u should remember log 2 =0.301