If one root of a quadratic equation is 2 - i , what is the equation?
other root = 2+i
(x-(2-i))(x-(2+i)) can u solve further >?
How do we know that's the other root?
COMPLEX ROOTS ALWAYS OCCUR IN PAIRS if a+ib is one root, a-ib is other root
Okay I'm remembering that now! But how do we formulate the equation?
if a is the root, x-a is the factor
Can you explain further please
since 2-i is a root, x-(2-i) is a factor since 2+i is a root, x-(2+i) is a factor since its a quadratic equation, it only has 2 factors which are (x-(2-i))(x-(2+i)) now just multiply them out
or use (a-b)(a+b) = a^2-b^2
[(x-2) + i ][(x-2)-i] = (x-2)^2 - i^2 getting this ?
I'm piecing it together give me a sec
I got x^2 - 4x + 5 = 0! Wow that's amazing! Thank you so much! Explains it much better than Dr. Chung's book
lol, welcome ^_^
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