If one root of a quadratic equation is 2 - i , what is the equation?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
other root = 2+i
hartnn (hartnn):
(x-(2-i))(x-(2+i))
can u solve further >?
OpenStudy (3psilon):
How do we know that's the other root?
hartnn (hartnn):
COMPLEX ROOTS ALWAYS OCCUR IN PAIRS
if a+ib is one root, a-ib is other root
OpenStudy (3psilon):
Okay I'm remembering that now! But how do we formulate the equation?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
if a is the root, x-a is the factor
OpenStudy (3psilon):
Can you explain further please
hartnn (hartnn):
since 2-i is a root, x-(2-i) is a factor
since 2+i is a root, x-(2+i) is a factor
since its a quadratic equation, it only has 2 factors which are
(x-(2-i))(x-(2+i))
now just multiply them out
hartnn (hartnn):
or use (a-b)(a+b) = a^2-b^2
hartnn (hartnn):
[(x-2) + i ][(x-2)-i] = (x-2)^2 - i^2
getting this ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (3psilon):
I'm piecing it together give me a sec
OpenStudy (3psilon):
I got x^2 - 4x + 5 = 0! Wow that's amazing! Thank you so much! Explains it much better than Dr. Chung's book