Question

factor: 27x^3y^6+8p^3

Answer 1

can u write 27x^3y^6 as (....)^3
what is .... ?

Answer 2

what?

Answer 3

27 is cube of what number ?

Answer 4

3

Answer 5

yes, so u can write
\(\huge 27x^3y^6 = (3xy^2)^3\)
got this ?

Answer 6

no

Answer 7

(3xy^2)^3 = 3^3 x^3 (y^2)^3 = 27 x^3 y^6
now ?

Answer 8

the answer is \[(3xy^2+2p)(9x^y^4-6xy^2p+4p^2)\]

Answer 9

just dont knw how to get it

Answer 10

\(\huge 27x^3y^6 = (3xy^2)^3 \\ \huge 8p^3= (2p)^3\)
now use
\(\huge a^3+b^3 = (a+b)(a^2-ab+b^2)\)

Answer 11

taking a= (3xy^2) and b= 2p

Answer 12

First rewrite as a sum of cubes

27x^3y^6+8p^3

(3xy^2)^3+8p^3

(3xy^2)^3+(2p)^3


Then use the sum of cubes factoring formula a^3 + b^3 = (a+b)(a^2 - ab + b^2) to get

In this case, a = 3xy^2 and b = 2p

(3xy^2 + 2p)( (3xy^2)^2 - (3xy^2)*(2p) + (2p)^2 )

(3xy^2 + 2p)( 9x^2y^4 - 6xy^2p + 4p^2 )

Answer 13

thank you for explaining lol

Answer 14

yw