there are 12 nickels, dimes, and quarters whose total value is $1.55. if the number of nickels exceeds the numbers of quarters by 1, how many coins of each kind are there?

Question

anonymous · Answer

.5x+.10y+.25z=1.55 or 5x+10y+25z=155

anonymous · Answer

what?

anonymous · Answer

Let n, d and q equal the number of nickles, dimes and quarters respectively.
Solve the following for n d and q.$$\{5n+10d+25q=155,n+d+q=12,n=q+1\}$$$$\{n=5,d=3,q=4\} $$

anonymous · Answer

Original posting had an error in the third equation.

anonymous · Answer

i understand now... the book has examples but its messy, thank you

anonymous · Answer

how did you get 12?

anonymous · Answer

nevermind

anonymous · Answer

In this class of problems I found it better to deal with pennies.
Thank you for the medal.

anonymous · Answer

easier