Question

there are 12 nickels, dimes, and quarters whose total value is $1.55. if the number of nickels exceeds the numbers of quarters by 1, how many coins of each kind are there?

Answer 1

.5x+.10y+.25z=1.55 or 5x+10y+25z=155

Answer 2

what?

Answer 3

Let n, d and q equal the number of nickles, dimes and quarters respectively.
Solve the following for n d and q.\[\{5n+10d+25q=155,n+d+q=12,n=q+1\}\]\[\{n=5,d=3,q=4\} \]

Answer 4

Original posting had an error in the third equation.

Answer 5

i understand now... the book has examples but its messy, thank you

Answer 6

how did you get 12?

Answer 7

nevermind

Answer 8

In this class of problems I found it better to deal with pennies.
Thank you for the medal.

Answer 9

easier