Question

\[\lim_{x \rightarrow 1 } \frac{ 1 }{ \ln(x) } - \frac{ 2 }{ x ^{2} -1}\]

Hopital

Answer 1

take lcm..if u want to use Hospital's rule

Answer 2

lim x--->1 { x^2 -1 - 2lnx}/ {lnx* (x^2-1)}

Answer 3

now it's the form of 0/0
use hospital's rule...

Answer 4

does it help u?

Answer 5

\[\frac{ (x ^{2} - 1) - 2 (\ln(x)) }{ \ln(x) (x ^{2} - 1) }\]

Answer 6

yes...now differentiate numerator and denominator

Answer 7

u know Hospital's rule?

Answer 8

yes i know

Answer 9

lim x--->a f(x)/g(x) = lim x--->a f'(x)/ g'(x)

if f(a) and g(a) both approaches zero or infinity

Answer 10

ok...then differntiate the numerator and denominator

Answer 11

okk