Question

A rock falls from rest a vertical distance of 0.72 meter to the surface of a planet in 0.63 second. What is the magnitude of the acceleration due to gravity on the planet?

Answer 1

use the formula
S = ut + 1/2 at^2

where u = 0
t = 0.63 seconds
s= 0.72 meter

Answer 2

So, .72m = 0(.63s) + 1/2 a (.63^2)?

Answer 3

yaa..

Answer 4

Ok I got 2.3. Is that correct?

Answer 5

2.3m/s^2

Answer 6

noo ... i getting as 3.628 m/s^2

Answer 7

u must have missed the square.... u must square the time ...

Answer 8

Maybe my calculations were wrong.
When I divided 1/2, I multiplied 2 on both sides. .72x2=1.44. After that I divided 1.44 by .63s which got me 2.3 :/

Answer 9

Ohhh

Answer 10

got it ??

Answer 11

Yea
Thanks!

Answer 12

ok..:)